Question

[x^((4n^2)+n)]/[x^(n+1)^(n-1)] *problem in comments*

Answer 1

\[(x^{4n ^{2}+n})\div (x ^{n+1})^{(x-1)}\]

Answer 2

x^((4n^2)+n)-(n^2-1))=x^(3n^2 +n+1)

Answer 3

Denominator use the property :- \(\Large{{(x^b)^c=x^{bc}}}\)

Answer 4

Is it ?

\[\large \frac{x^{4n^2 + n}}{(x^{n+1})^{n-1}}\]

Answer 5

using this property what do u get as denominator @spasta106 ??

Answer 6

I got x^(n^2-1)

Answer 7

@waterineyes yes that's the problem

Answer 8

now use the property :- \(\Large{\frac{x^a}{x^b}=x^{a-b}}\)

Answer 9

Jitesh is guiding you very well @spasta106

Do what he is saying..

Answer 10

@spasta106 u will get \[\Huge{x^{(4n^2+n)-(n^2-1)}}\]

Answer 11

Yes, that's what I have so far

Answer 12

now solve this powers & u will get your answer :)

Answer 13

x^? @spasta106

Answer 14

Ok 3n^2+n+1?

Answer 15

with x as a base

Answer 16

I'm still getting the same answer...

Answer 17

ok ! now that is your answer :)

Answer 18

Ok! thanks!

Answer 19

yw :)