Question

pls.......answer the 25th question

Answer 1

pls.......HELP..

Answer 2

do you know how to add and subtract fractions?

Answer 3

yes\

Answer 4

that is all the first option is doing; it just looks messy

Answer 5

its looking too messy 4 me
.help

Answer 6

\[\frac{m+n}{p+q}-\frac{m-n}{p-q}\]
\[\frac{(m+n)(p-q)}{(p+q)(p-q)}-\frac{(p+q)(m-n)}{(p+q)(p-q)}\]
\[\frac{(m+n)(p-q)-(p+q)(m-n)}{(p+q)(p-q)}\]

Answer 7

\[\frac{(m+n)(p-q)-(p+q)(m-n)}{(p+q)(p-q)}\]
\[\frac{mp-nq+np-mq-mp-mq+np+nq}{p^2-q^2}\]
\[\frac{\cancel{mp}\cancel{-nq}+np-mq\cancel{-mp}-mq+np\cancel{+nq}}{p^2-q^2}\]
\[\frac{2np-2mq}{p^2-q^2}\]
\[\frac{2(np-mq)}{p^2-q^2}\]

Answer 8

@amistre64 it is being shown to me :
Math Processing Error]
[Math Processing Error]
[Math Processing Error]
[Math Processing Error]
[Math Processing Error]

Answer 9

mathslover, try doing a hard caache reset:

Ctrl+f5

Answer 10

OK, let me try

Answer 11

otherwise, its prolly just telling you that i messed it up big time :)

Answer 12

:) , it is working now, sorry for interrupting and must say "excellent work sir"

Answer 13

yay!!

Answer 14

\[\frac{7+3\sqrt{5}}{3+\sqrt{5}}-\frac{7-3\sqrt{5}}{3-\sqrt{5}}=a+\sqrt{5}b\]
\[\frac{(7+3\sqrt{5})(3-\sqrt{5})-(7-3\sqrt{5})(3+\sqrt{5})}{(3+\sqrt{5})(3-\sqrt{5})}=a+\sqrt{5}b\]
\[\frac{(21-7\sqrt{5}+9-15)-(21+7\sqrt{5}-9-15)}{3^{2}-(\sqrt{5})^{2}}=a+\sqrt{5}b\]
\[\frac{(15-7\sqrt{5})-(-3+7\sqrt{5})}{9-5}=a+\sqrt{5}b\]
\[\frac{(15-7\sqrt{5})-(-3+7\sqrt{5})}{4}=a+\sqrt{5}b\]
\[\frac{15-7\sqrt{5}+3-7\sqrt{5}}{4}=a+\sqrt{5}b\]
\[\frac{18-14\sqrt{5}}{4}=a+\sqrt{5}b\]
\[\frac{9-7\sqrt{5}}{2}=a+\sqrt{5}b\]
\[\frac{9}{2}-\frac{7\sqrt{5}}{2}=a+\sqrt{5}b\]
Now comparing LHS and RHS,
\[a=\frac{9}{2}\] and \[\sqrt{5}b=\frac{-7\sqrt{5}}{2}\]
\[b=\frac{-7}{2}\]

Answer 15

lol , direct solution ;)

Answer 16

isn't,.....\[3\sqrt{5}\times3=9\sqrt{5}\]

Answer 17

that it is

Answer 18

using

m=7
n=3sqrt(5)
p=3
q=sqrt(5)

\[\frac{2(np-mq)}{p^2-q^2}\]
\[\frac{2((3)3\sqrt{5}-7\sqrt{5})}{3^2-\sqrt{5}^2}\]
\[\frac{2(9\sqrt{5}-7\sqrt{5})}{9-5}\]
\[\frac{2(2\sqrt{5})}{4}=\sqrt{5}\]

so i might be wrong ....

Answer 19

wat?

Answer 20

youll have to be more concise as to what your confusion may be ...

Answer 21

in @shubham.bagrecha 's answer 3sqrt5 x 5 is wrong @amistre64

Answer 22

i agree that shub has a few typos :)

i like mine better, its much cleaner to read thru

Answer 23

for comparison tho:

http://www.wolframalpha.com/input/?i=%287%2B3sqrt%285%29%29%2F%283%2Bsqrt%285%29%29-%287-3sqrt%285%29%29%2F%283-sqrt%285%29%29

Answer 24

looks like

0 + sqrt(5)*1

is a good answer tho

Answer 25

but how do we get the answer.... @amistre64

Answer 26

in my method, a generalized the values into variable; and worked thru the structure to simplify the form

then i inserted the specific values into their proper place holders to determine the solution

Answer 27

but u gt the ansr sqrt5 ....nt 0+sqrt5x1

Answer 28

is there any difference btw. the two?@basith

Answer 29

yes, which means that by comparison to:

a + sqrt(5) b ; that a=0 and b=1

Answer 30

cn u hlp me with the 2nd part too... :)

Answer 31

do you understand the first part?

Answer 32

yes......thnx 4 tht :)

Answer 33

then how can we use the knowledge from that to work out a suitable result for the second part?

Answer 34

first, generalize with variables\[\frac{a}{p-q}\]
then work thru the structure to conform it to what they are asklng for ...

how do we rationalize a denominator?

Answer 35

pls.....wait a min

Answer 36

\[\frac{ 25\sqrt{40}+25\sqrt{80} }{ -40 }\]
then wat

Answer 37

then you can unravel the sqrts. they have perfect square factors that can be pulled out to conform them to:

x sqrt(5) and ysqrt(10)

Answer 38

is it 7.905

Answer 39

@amistre64

Answer 40

im getting -9.xxxx

Answer 41

notice that you have a negative on the bottom, and a positive value up top; regardless of what the specifics are; the answer will have to be negative

Answer 42

the rest of it is just keeping track of your operations