Question

Having trouble with an integral:

Answer 1

integrals can be troublesome

Answer 2

\[\int\limits_{ }^{} \frac{1}{P(P-5)}dP\]

Answer 3

decomp

Answer 4

i split it to be 1/p and 1/(p-5) and tried to integrate by parts but it doesn't seem to work out nicely. any help would be appreciated

Answer 5

\[\large{\int {\frac{1}{P(P-5)}dP}}\]

\[\large{\int {\frac{1}{P}dP}\int \frac{1}{P-5}dP}\]

Answer 6

Whoa Nelly

Answer 7

answer will be zero?

Answer 8

you can't split an integral like that

Answer 9

\[\frac{1}{P(P-5)}=\frac{A}{P}+\frac{B}{(P-5)}\]
\[1=A(P-5)+BP\]
when P=0, A=-1/5
when P=5; B=1/5

Answer 10

i just realised that its probably partial fractions

Answer 11

well there you go :)

Answer 12

\[-\frac15\int\frac1Pdp~+~\frac15\int\frac1{P-5}dp\]