Question

Limits anyone? D:

Answer 1

I have NONE !

Answer 2

Are u the one that I will agree to take upon myself them ?!

Answer 3

\[\lim_{x \rightarrow } \frac{4^{x+1}-6^x}{5^x-8^x}\]

Answer 4

@hartnn

Answer 5

x tending to infinity

Answer 6

x-> infinity or 0 ??

Answer 7

infinity

Answer 8

lim x-> 0 (a^x-1)/x = ln a
how to use it here

Answer 9

:/idk

Answer 10

infinity / neg. infinity? (indeterminate form)

Answer 11

DIVIDE ALL TERMS BY \[8^x\] this changes nothing but shows immediately that the expression's limit is 0 (zero)

Answer 12

As is well known\[ \lim_{x \to \infty} a^x =0 \,\,\,if\,\,\,\,|a|<1\]

Answer 13

@DLS won't mind a medal for that either...

Answer 14

what's ur ans?

Answer 15

i didnt get it

Answer 16

\[ \frac{0}{1} = 0\]

Answer 17

im getting 2/-1

Answer 18

Really - divide all the terms by 8^x - you get expression tending to 0 except a single expression in the denominator which is identically 1.

Answer 19

\[\frac{4^x.4-6^x}{5^x-8^x}\]

Answer 20

mdl or not I solved you the question, and you have to follow and analyze the provided solution. Medal is optional , but so is further help...

Answer 21

Dividing by 8^x
\[\frac{2-6^x}{5x/8x-1}\]

Answer 22

\[ \frac{4^x}{8^x}=(\frac{1}{2})^x \rightarrow 0\]

Answer 23

why not 1/2?

Answer 24

Do ypur algebra CORRECTLY. REPEAT - CORRECTLY !!!

Answer 25

OHYEAH O.o