Write a polynomial of minimum degree in standard form with real coefficients whose zeros include those listed. 5 and 3+2i
Do I set this up as: (x+5)(3+2i)
@amistre64
if 5 is a zero of polynomial, then (x-5) is one factor
So, (x-5)(x+5)(3+2i)(3-2i) ?
only complex zeroes come in pairs, not real ones
So, what does that mean?
since 3 + 2i, is a zero, 3-2i is also a zero. so, (x- (3+2i)) and (x - (3-2i)) are factors of the polynomial
since 5 is also a zero, you have (x-5) as another factor
Okay, so only (x-5) and not (x+5)?
thats right !
So, the polynomial will be (x-5)(x-(3+2i)(x-(3-2i)) after being foiled?
Perfect !
Okay, so foil those and then my answer is whatever I get?
hmm wait a sec plz im not getting real coefficients .. .we may need @amistre64 help
Okay.
(3+2i) is a zero, not a factor
and since all complex numbers come with a conjugate (x-5) (x-(3+2i) (x-(3-2i)) should be the factors right?
Yes.
just did a quick wolf on it, and it works out; ganesh, just check the algebra :)
Is it x^3-11x^2+43x-65 ?
x -3 -2i x -3+2i .... yes
ohh yes i see thnks :D
I didn't figure that out... it's the answer the book gives me. Still don't know how to get it after finding zeros
x -3 -2i x -3+2i --------- x^2-3x-2ix -3x +9+6i 2ix -6i -4i^2 ---------------------- x^2-6x +9 -4i^2 ^^^ = 4 x^2 -6x +13 x -5 ------------ x^3 -6x^2 +13x -5x^2 +30x -65 ------------------- x^3-11x^2+43x -65
"FOIL" is a memory aid, and is not very good at things that have more than 2 terms each. the real math is to simply do multiplication like you was taught in the 3rd grade
i tend to have a left to right appraoch for polys; it just helps me keep track of things easier a right to left approach is fine as well if that makes you more comfortable
Okay. But I'm getting the same thing using foil.
"FOIL" in this case would, as long as you define what you are using for you terms, would be fine. i just feel it gets a bit convoluted
Okay, and I get what you mean. But thanks for the help, it's greatly appreciated!
youre welcome
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