Question

\large lim_{x rightarrow 0} frac{2sinx-sin2x}{x^3}

Answer 1

\[\large \lim_{x \rightarrow 0} \frac{2sinx-\sin2x}{x^3}\]

Answer 2

write sin 2x as 2 sin x cos x

Answer 3

already did

Answer 4

\[\large \lim_{x \rightarrow 0} \frac{2sinx-2sinxcosx}{x^3}\]

Answer 5

take sin x common

Answer 6

\[\large \lim_{x \rightarrow 0} \frac{2sinx(1-cosx)}{x^3}\]

Answer 7

already did

Answer 8

stuck here

Answer 9

write one of the x under sin x
and use sinx/x =1

Answer 10

2sinx or sinx?

Answer 11

will i be left with?:
2(1-cosx)/x^2?

Answer 12

yup.

Answer 13

ill be left with 1 right?

Answer 14

now multiply and divide by 1+cos x

Answer 15

okay

Answer 16

thenn?

Answer 17

what is (1+cos x)(1-cos x)

Answer 18

sin^2x

Answer 19

2/2=1

Answer 20

and u have x^2 in denominator, right ?

Answer 21

right 2 is correct

Answer 22

sorry 1

Answer 23

:D yayy!!