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Writing 14 Online
OpenStudy (anonymous):

How do I do this problem? I know the limit approaches zero. lim x approaches pi/2 from the right e superscript (tan x).

OpenStudy (anonymous):

1) Consider that x->pi/2 from the left: Lim(x->pi/2-)e^tanx= Lim(h->0)e^tan(pi/2-h)= (h>0 & is real) inf. 2)consider that x->pi/2 from the right: Lim(x->pi/2+)e^tanx= Lim(h->0)e^tan(pi/2+h)= (h>0 & is real) inf im not absolutly sure that this is right

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