Question

Sketch the graph of the function below, being sure to include at least two full periods. y=sin(x+pi/4).

Here's what I am starting to understand?
So, my amp =3/4 and period of one cycle is 2pi/1?

Answer 1

amplitude is 1 , y=1sin(x+pi/4)

Answer 2

@sam...I kinda wrote that wrong..

Answer 3

I looked at the other problem above the one I shared. I wanted to share y=3/4 sin (2pi-pi).

Answer 4

My amplitude is 2pi/1?

Answer 5

\[y=\frac{3}{4} \sin (2\pi-\pi)\]
This one?

Answer 6

YES! Thanks. That's it!

Answer 7

:)

Answer 8

are you sure its sin(2PI-PI)?

Answer 9

lol. It is sin(2x-pi)....thanks for hanging in there.

Answer 10

\[y=\frac{3}{4} \sin (2x-\pi)\]
So the amplitude is 3/4

Answer 11

I agree. My period is? That's the part that is hard to see just by looking at it. Just wondering if there's a way to do that because I need to learn to do this more quickly.

Answer 12

would I look at the -pi for the amplitude? I have seen this done two different ways. I am trying to make it work for me.

Answer 13

Formula
\[y = Asin(bx + c) + d\]
\[T=\frac{2\pi}{b}\]

Answer 14

So, the period ,\[T=\frac{2\pi}{2}=\pi\]

Answer 15

how did you know to use those numbers.

Answer 16

The formula to find period is \(T=\frac{2\pi}{b}\)
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So,
\[y=\frac{3}{4} \sin (2x-\pi) \\ \\ \Big\downarrow \\ \\ y=Asin(bx+c)\]
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b is 2,
\[T=\frac{2\pi}{2}=\pi\]

Answer 17

cool...thanks!

Answer 18

Ok, so here's an example of how my prof. does this.

Answer 19

y=sin(x+pi/4) (no period, no change no amp)..maybe a bad example. The best I could find .