Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities include those listed. 2(multiplicity 2), 3+i(multiplicity 1)
I know that all complex numbers have a conjugate.. but this is multiplying, the other was adding.
w has multiplicity of 2, whats the factors ?
I think (x-2)^2 (x+2)^2
*2 has multiplicity of 2, whats the factors ?
no again, real zeores font come in pairs, only complex zeroes come in pairs
*dont
Sorry /: I was thinking complex for a second. But it is (x-2)^2
correct !
work out the complex zero
And since complex numbers have conjugates then.. the next two zeros would be: (x-(3+i)) and (x-(3+i)) and since multiplicity is one... there is no power.
And since complex numbers have conjugates then.. the next two zeros would be: (x-(3+i)) and (x-(3\(\color{red}{-}\)i)) and since multiplicity is one... there is no power.
Oh, simple mistake. Thanks for fixing that :P
So now I just multiply those for standard form :)
:) you mastered these, awesome !
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