Question

State how many complex and real zeros the function has.

f(x)=x^3-x+3

I think that + or - 3 is one.. but I don't know how to figure out the complex zeros.

Answer 1

2

Answer 2

How?

Answer 3

u want me to give u the formula?

Answer 4

Yeah.

Answer 5

lol u doing FLVS grr hate that

Answer 6

i tried it out didnt like it went to american homeschool

Answer 7

@ganeshie8 Do you know?

Answer 8

do u have a graph calc?

Answer 9

Yuuup.

Answer 10

f(x)=x^3-x+3

since its degree is 3, there will be exactly 3 zeroes for sure

Answer 11

Okay.. so; x=3, x=-3, and x=1 ? Maybe?

Answer 12

heres an example ----Consider the polynomial function f ( x ) = 2 x3 + 3 x2 + 8 x - 5. Notice that it is written in standard form for polynomials, that is, terms are written in decreasing order according to their exponents. Now, count the number of changes in sign of the coefficients. There is exactly one such change in sign. Thus, there can be only one positive zero.

Answer 13

Ohh yeah Descartes' Rule!

Answer 14

gl with school @AmberBamber

Answer 15

But how do I figure out complex zeros?

Answer 16

& thanks. :)

Answer 17

@AmberBamber umm let me look in my textbook lol pm me u gotta give me a minute too look for that chapter

Answer 18

to find the complex zeroes, we need to know real zeroes first (+ve and -ve)

Answer 19

f(x)=x^3-x+3

how many sign changes u see ?

Answer 20

in f(x).. 1 sign change.
in f(-x).. 2?