Question

Complete the algebra to show the function
\[f(x)= 2(2x-3)(2)(4x+5)^3 -(2x-3)^2 (3)(4x+5)^2 (4) \div (4x+5)^6 simplifies to -8(2x-3)(x-7)\div (4x+5)^4 \]

Answer 1

simplifies to \[-8(2x-3)(x-7)\div (4x+5)^4 \]

Answer 2

factor out a (2x-3) and a (4x+5)^2 (numerator)

Answer 3

Can you show me how this is done? I cant figure it out

Answer 4

\[(2(2x−3)(2)(4x+5)^{3}−(2x−3)^{2}(3)(4x+5)^{2}(4))\]
\[(4x+5)^{2}*(2(2x−3)(2)(4x+5)−(2x−3)^{2}(3)(4))\]

Answer 5

\[\frac{ (4x+5)^{2}*(2(2x−3)(2)(4x+5)−(2x−3)^{2}(3)(4)) }{ (4x+5)^{6} }\]

Answer 6

ok?

Answer 7

yes thank you!