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Mathematics 16 Online
OpenStudy (anonymous):

Let T:R3->R3 be multiplication by the matrix 1 0 3 1 2 4 1 8 5 find a basis for the range of T find a basis for the kernel of T

OpenStudy (anonymous):

by reducing the matrix i found this |dw:1348858057958:dw| does it means my range is {(1,0,0),(0,1,0),(0,01)} and kernel be (0,0,0)

OpenStudy (anonymous):

@Zarkon

OpenStudy (anonymous):

@Coolsector

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

how to check the rank and nullity

OpenStudy (anonymous):

@experimentX on this matrix

OpenStudy (experimentx):

the rank is 3 of course.

OpenStudy (anonymous):

so the nullity is 0?

OpenStudy (experimentx):

looks like i need to look on wikipedia http://en.wikipedia.org/wiki/Rank%E2%80%93nullity_theorem

OpenStudy (anonymous):

ok i got it thnx

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