Question

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Answer 1

note that\[S (x-1)= (x-1)(1 + x + x^2 +.. + x^{2011})=x^{2012}-1\]

Answer 2

does that help?

Answer 3

I'm not making the connection on how to use that fact

Answer 4

is it ok with first one?

Answer 5

Yes that is good

Answer 6

Just trying to work it out on paper over here

Answer 7

ok

Answer 8

thats a usefull identity try to work it out\[x^n-1=(x-1)(x^{n-1}+x^{n-2}+...+x^2+x+1)\]

Answer 9

When I get to S(x-1) = 7x-7, what is next?

Answer 10

it obvious that \(x\neq 1\) so u can divide both sides by x-1

Answer 11

S=?

Answer 12

oh, ok

Answer 13

I got it.

Answer 14

holy number :)

Answer 15

I should mention that when x=1, S=2012

Answer 16

yup

Answer 17

ok. Thank you once again mukushla :)

Answer 18

no problem

Answer 19

You made this so simple
haha

Answer 20

I thought I would be far in summation algebra