Find the distance between the points L(10, 14) and M(-8, 14).
Pythagorean theorem. Draw the right triangle that has the line segment LM as its hypotenuse.
distance formula would better suit this case.
@nestor18, The distance formula *is* the pythagorean theorem.
yea i used it but couldnt figure out how they got the last part
A simplification here is that both points are at the same height above the x-axis, so that can be ignored. Just find the difference between -8 and 10.
o ok thanks
i figured it that part out but how do u find the rest of it
It really helps to draw a picture of the situation: |dw:1348866314160:dw|
Elementary counting or addition will solve this one.
Yes, I know just a different way to interpret it though. Seeing there is two coordinates and not a triangle I find it easier if he would research the distance formula by name since most people know pythagoreans theorem a^2+b^2=c^2
so then it would just be -18+0
Nestor18 suggests doing this: \[d=\sqrt{(10 - (-8))^2+(14-14)^2}\] I recommend this: \[d=8+10\]
They are equivalent, but I'd rather just look at the picture and see that -8 is 8 units away from 0 and 10 is 10 units away from 0, so the total distance is 8+10. Understand?
o ok yea do
i understand but whats the answer
? I'm confused. You don't know what 8+10 is?
nevermind
theres another part to it
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