The equation of the line that goes through the points (-8,7) and (3,3) can be written in general form Ax+Bx+C=0 where:
A=
B=
C=

Question

The equation of the line that goes through the points (-8,7) and (3,3) can be written in general form Ax+Bx+C=0 where:
A=
B=
C=

hero · Answer

You can at least begin with y = mx + b and insert points this way.

anonymous · Answer

I did & I came up with y=-4/11x+45/11

hero · Answer

you began with 

7 = -8m + b
3 =   3m + b

?

hero · Answer

@RoLexx

anonymous · Answer

why did you start like this (I'm curious & will like to know)

hero · Answer

Because if you did that, you could find m and b this way

7 = -8m + b
3 =   3m + b

7 + 8m = b
3 - 3m = b

b = b

7 + 8m = 3 - 3m
8m + 3m = 3 - 7
11m = -4
  m = -4/11

b = 7 + 8(-4/11)
b = 7 + -32/11
b = 77/11 - 32/11
b = 45/11

y = -4/11x + 45/11

y = (-4x + 45)/11

11y = -4x + 45

4x + 11y = 45
4x + 11y - 45 = 0

hero · Answer

@RoLexx

hero · Answer

therefore

A = 4
B = 11
C = -45

anonymous · Answer

OMG That makes so much sense thanks @Hero