Question

I need help solving this equation. 6r^2+11r=10. My answers are r+and- i5/2 squared and r+and- 2/3 squared...I am wrong apparently.

Answer 1

6r^2+11r=10
6 r^2 + 11r - 10 = 0
@Amandarangel18
Factor: 6 r^2 + 11r - 10 = 0.
After that, you can use the Zero Product Property to get the roots.

Please post what you get when you factor 6 r^2 + 11r - 10 = 0.

Then, we can compare results.

Answer 2

@Amandarangel18

I need help solving this equation - I'm trying to help.

Answer 3

On this problem you need to rearrange 6r^2+11r=10 to be
6r^2+11r-10=0
Then use the quadratic formula to solve. \[-b \pm \sqrt{b ^{2}-4ac}\div2a\]
Which then gives: \[-11\pm \sqrt{11^{2}-4(6)(-10)}\div2(6)\]
So r=2/3, -5/2
Plug those values back in to the original equation for r and you'll see the solution works out.

Answer 4

@jonnymiller
OpenStudy values the Learning process - not the ‘Give you an answer’ process •Don’t post only answers - guide the asker to a solution.
http://openstudy.com/code-of-conduct

Answer 5

I did guide the asker to a solution!

Answer 6

There is no way that anyone outside of @jonnymiller thinks that what he did was "to guide" ...

Answer 7

In jonnymiller's defense, I already did the problem and finished it before I posted the equation. Hence, the answer in the question that I asked. We both got the same answer, but that answer is wrong apparently. According to my math book.

Answer 8

I found out that I didnt rationalize which kept me from getting the correct answer. I missed the last step which was to rationalize.