Question

find the slope of the line through each pair of points
(3/2,-1/2) and (-2/3,1/3)

Answer 1

y2-y1/x2-x1

Answer 2

1/3 - (-1/2)/ -2/3 - 3/2

Answer 3

get it? just find the answer

Answer 4

Insert each point into y = mx + b as follows:

-1/2 = 3/2(m) + b
1/3 = -2/3(m) + b


Isolate b in each:

-1/2 - 3/2m = b
1/3 + 2/3 m = b

set b = b

-1/2 - 3/2m = 1/3 + 2/3m

Place like terms on both sides:
-1/2 - 1/3 = 2/3m + 3/2 m
-3/6 - 2/6 = 4/6m + 9/6m
-5/6= 13/6m

Multiply both sides by 6/13
-5/13 = m

Answer 5

Remember slope is equal to rise/run so you take the rise or the difference of the y coordinates and divide them by the difference of the x coordinates so you get:

\[m=\left( y _{2} - y _{1}\right)\div \left( x _{2}-x _{1}\right)\]

\[\left( 1/3-(-1/2) \right)\div \left( (-2/3)-3/2 \right)\]

m=-5/13