Question

Two angles form a linear pair. The measure of one angle is four times the measure of the other angle. Find the measure of each angle.
Please help! I have no idea what to do! >.<

Answer 1

Ok, so we have two angles: \(a\) and \(b\).
They form a linear pair so: \(a+b = 180^\circ \)
We also know that \(a = 2b\) since one is twice the size of the other.
Thus we substitute \(2b\) into \(a\) in the first equation to get:
\[2b + b = 180^\circ \]
\[3b = 180^\circ \]
\[b = 60^\circ \]
Then we substitue \(60^\circ \) into \(b\) in our second equation:
\[a+60^\circ =180^\circ \]
\[a =120^\circ \]
So there we have it. \(a=120^\circ , b=60^\circ\)

Answer 2

Actually, this is the case where one is twice the size of the other.
So it should be \(a=4b\) for our second equation. Sorry.

But think you can do it?

Answer 3

I can redo it the correct way if you'd like. But you should try if yourself first.

Answer 4

a+b= 180
a=4b
3b+b=180
4b=180
b=45
?

Answer 5

then substitute?

Answer 6

No
a+b= 180
a=4b
4b+b=180 <--- this is what it should be here.

Good work though, you're getting there.

Answer 7

b=36, a=144 ?