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OpenStudy (anonymous):
For t!=0, f(t) = 1-(1/t). Do you know how to derive that?
OpenStudy (anonymous):
Do you mean \[\frac{t-1}{t}\]
or \[t-\frac{1}{t}\]?
OpenStudy (anonymous):
the second one
OpenStudy (anonymous):
Oh nvm forget my answer then.
OpenStudy (anonymous):
Well you're just doing two separate derivatives then. One for t, and one for -1/t. Can you do these separately?
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OpenStudy (anonymous):
no i wouldn't have asked othewrwise
OpenStudy (anonymous):
i think the derivative of t is zero
OpenStudy (anonymous):
You don't know what the derivative of t is?
OpenStudy (anonymous):
or 1
OpenStudy (anonymous):
No, 0 is only the derivative of a constant. For example, the derivative of the number 5 is 0. t is a variable that changes, so its derivative can't be 0 (that would imply it's not changing). Yes, 1 is correct for t.
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OpenStudy (anonymous):
now -1/t?
OpenStudy (anonymous):
Use to power rule:
\[\frac{d}{dx}x^n = n\cdot x^{n-1}\]
In the first case, n = 1, and in the second case n = -1.
OpenStudy (anonymous):
If you know the power rule, you can use it to derive -1/t by first rewriting it as \[-t^{-1}\]