Question

A force F applied to an object of mass m produces as acceleration of 3 m/s^2. The same force applied to a second object of mass M produces an acceleration of 1 m/s^2. (a) What is the ratio of m/M? (b) If m and M are combined, find their acceleration under the action of the force F.

Answer 1

Attempt to the solution:
a.) m/M = A/a= 1/3= 0.333
b.) F= m(3m/s^2)
m= F/3m/s^2
F= M(1m/s^2
M= F/(1m/s^2))

m+M = F/3 m/s^2 + F/(1m/s^2)
=F+3F/3m^2/s^4
m+M = 4F/(3m/s^2)
F= ma
m(3m/s^2)= [(4F)/(3m/s^2)](a)
a= {[(F/3m/s^2)](3m/s^2)}/{(4F)/(3m/s^2)}
a= 3 m/s^2/4
a= (3/4) m/s^2

is that correct?

Answer 2

@sauravshakya :)