What are the algebraic steps involved in transforming
\[(x+5)/x \] into \[1-5/(x+5)\]
this minus how you have got it ?
these are just the reciprocals of each other.....what does the question need?
so and the denominator is just x and not plus 5
Sorry @hartnn, could you explain that with a bit more detail.
I'm afraid I don't quite see yet how they are reciprocals
in 3A2-j, there was (x+5)/x which when the denominator is separated becomes x/x+5/x = 1+5/x thats it....why do u ask about 1-5/(x+5) ?
grr im sorry its k) not j)
my fault
okk
\(\huge \frac{x}{x+5}=\frac{x+5-5}{x+5}=\frac{x+5}{x+5}-\frac{5}{x+5}\) did u get this ?
added and subtracted 5 in numerator to get x+5
no i didnt get this, thats why i was asking. but your explanation is great and exactly what i was looking for. now i completely get it.
thank you :)
ok, welcome ^_^
Join our real-time social learning platform and learn together with your friends!