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OpenStudy (anonymous):
What are the algebraic steps involved in transforming
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OpenStudy (anonymous):
\[(x+5)/x \] into \[1-5/(x+5)\]
jhonyy9 (jhonyy9):
this minus how you have got it ?
hartnn (hartnn):
these are just the reciprocals of each other.....what does the question need?
jhonyy9 (jhonyy9):
so and the denominator is just x and not plus 5
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OpenStudy (anonymous):
Sorry @hartnn, could you explain that with a bit more detail.
OpenStudy (anonymous):
I'm afraid I don't quite see yet how they are reciprocals
hartnn (hartnn):
in 3A2-j, there was (x+5)/x
which when the denominator is separated becomes x/x+5/x = 1+5/x
thats it....why do u ask about 1-5/(x+5) ?
OpenStudy (anonymous):
grr im sorry
its k) not j)
OpenStudy (anonymous):
my fault
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hartnn (hartnn):
okk
hartnn (hartnn):
\(\huge \frac{x}{x+5}=\frac{x+5-5}{x+5}=\frac{x+5}{x+5}-\frac{5}{x+5}\)
did u get this ?
hartnn (hartnn):
added and subtracted 5 in numerator to get x+5
OpenStudy (anonymous):
no i didnt get this, thats why i was asking. but your explanation is great and exactly what i was looking for. now i completely get it.
OpenStudy (anonymous):
thank you :)
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hartnn (hartnn):
ok, welcome ^_^
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