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OpenStudy (anonymous):

Why the speed of light is constant?(explain mathematically and logically)

OpenStudy (anonymous):

Mr. Einstein will be the best person to answer this .. I haven' read much about the theory of relativity but I can assure you that your answer lies there. Do a bit of research . I think of it as a natural law imposed on us, and we can't help it. I can't be of any more help to you.

OpenStudy (anonymous):

I am a logical person,i can't accept whatever exist in this nature just as it comes.Sorry,I deny with you

OpenStudy (anonymous):

Einstein explained it thus: speed of light is a geometric property , kind of "slope" in Minkowski geometry of space-time. Since this is a property of spacetime itself it does NOT change by going to moving rference frame of the observer. So we observe the same relation beteen geometry and spacetime also when we move.

OpenStudy (anonymous):

Not fully clear

OpenStudy (mayankdevnani):

http://van.physics.illinois.edu/qa/listing.php?id=2605

OpenStudy (mayankdevnani):

@nrdnandan

OpenStudy (anonymous):

speed of light is geometric property of spacetime. No change in movement therefore

OpenStudy (anonymous):

@Mikael buddy he is confused with the words 'geometric property of spacetime' he needs to know what does that mean, and how changes reference frames doesn't affect that property

OpenStudy (anonymous):

read tf introduction to special relativity

OpenStudy (anonymous):

@nrdnandan read what @Mikael has said

OpenStudy (anonymous):

The speed of light in vacuum is a universal constant, because when the light is refracted ie passes from one medium to another, its speed changes because the electrical and magnetic characteristics of the medium are different. You must remember that light is an electromagnetic wave. \[v=1/\sqrt{\epsilon_{0} \epsilon \mu _{0} \mu}\]

OpenStudy (anonymous):

in vacuum \[\epsilon _{},\mu _{} \] son iguales a 1 por ese motivo \[v=C \approx3.10^{8}m/s\]

OpenStudy (anonymous):

in vacuum \[\epsilon, \mu\] are equals 1

OpenStudy (anonymous):

\[v=C \approx3.10\]

OpenStudy (anonymous):

good luck

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