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Oh my this is just too hard for me...how do i solve this.. x^5 - x + 1 = 0
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Is this \(x^2-x+1=0\) ?
no \[x^{5} -x +1=0\]
hmm.....
a quintic equation
\(x^5-x=-1\)
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nop quintic...
sorry!
and its so hard to solve i don know
i m trying ok :)
ok
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this quintic equation's root can't be expressed as radicals .
No idea for the answer but does it help to start with:\[x \left( x ^{4} - 1 \right) = 1\]?
mmm...i think i can try from there...luckily i have the answer with me...
visually, the answer is somewhere ]-1.2;-1.1[
I don't know if it will converge, you could try Newton's method: Make a guess, say -1.25 (x_0) then x_1 = x_0 - f(0)/f'(0) and repeat till u get close..
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yeah i tried Newton method and got x=-1.1679 or closer to this
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