Question

how do u intergrate this?

x/(1+x^2)

Answer 1

show all steps please

Answer 2

I'll give you a clue. Take :
1+ x^2 = t.

Answer 3

1+x^2 =t
2x dx/dt = 1
2xdx = dt
so now ur problem becomes
Integration of dt / 2t (Note : 2 is multiplied and divided to get this form)
Now after integrating we get 1/2 log t
substitute t = x^2
1/2 log x^2
= log x
since it is not definite integral answer is log x +C