Question

What is \[S_n - S_{n-1}\]

Answer 1

\[S= ut +\frac{ 1 }{ 2 }a t^2\] use this and you are done , put t= n and t= n-1

Answer 2

there will be two equations

Answer 3

right and we get :
\[\large{S_n = u + \frac{a(2n-1)}{2}}\]

Answer 4

but can we prove that :
\[S_n - S_{n-1}=S_n\] ?

Answer 5

No because \[S _{n}\] is the distance traveled in nth second and S(n-1) is the distance traveled in (n-1) seconds, how could their difference be equal to distance traveled in n seconds ... think :)

Answer 6

*n seconds

Answer 7

not nth

Answer 8

yes very correct but the formula says S_n = u + a(2n-1)/2

Answer 9

Oh! OK, so it is S_nth = u + a(2n-1)/2 ?