Question

I need help with an algebra question! I am going to attach the file which contains the question. Please help me!!!! Thank you

Answer 1

There! Ignore the answers that I have already put! Please help me! Thanks!!

Answer 2

You would be removing 4 triangles whose area for each would be 1/2 b. h or 1/2 x^2 since there are 4 the total triangle area is 2x^2. Do you agree with this so far?

Answer 3

We would be removing 4x^2, isnt it?

Answer 4

oh wait my bad i get it! those are triangles!! yeah!!

Answer 5

so the function would be A = 64-2x^2, right?

Answer 6

No because area of triangle is \[b \times h \over 2\]since there are 4 corners the total triangles area is \[2\times b \times h\] since b=x and h=x it would be (total area) \[2x ^{2}\]

Answer 7

Yes you have solved for the function A=64-2x^2. Good now what was the rest of the problem?

Answer 8

the next one is: determine the domain of the function

Answer 9

The area can not become negative does that give you a hint?

Answer 10

yes, there the options are: 1.) 0 ≤ x < 4, 2.) 0 < x ≤ 4, 3.) 0 ≤ x ≤ 4, 4.) 0 < x < 4

Answer 11

zero cant be included in the domain because then that would mean the square is not cut at all. dont you think so?

Answer 12

Well x can range from 0 up to a maximum sq rt of 32 or 0<x<4*SqRt2

Answer 13

I think the second option is trying to say that but don't know for sure lol

Answer 14

Well what you suggest makes sense, but sometimes the writer of such problems does not think the same. Let me study the link some more.

Answer 15

so you think it is the last option? why? why taking a square root of 32?

Answer 16

ok

Answer 17

I'm back, rethinking this. I now see that x can not exceed 4 because of the 8 for each side of the square. When x = 4 the edge is gone! So that changes my thoughts, the area is not the limiting thing, the dimesnion of the sides are the limit. In view of this revelatioln
the Domain for x is 0 to 4. Now 0 would mean no cut at all, and if a cut is mandatory you would say 0<x</=4

Answer 18

I guess it is your call, there is a some ambiguity in my comphrension of this problem.

Answer 19

so if the domain includes 4 then the octagon becomes a rhombus, rihgt? thats what you mean when you said the edge will be gone?

Answer 20

did i confuse you? I am sorry

Answer 21

If x =4, you would have a square remaining with sides of 4 (I think lol) get a 8 in sq of paper and cut off the triangles whose sides are 4 and see whats left. At 73 yrs of age here, my imagination does not range very far lol, but it looks like there might be a square left but maybe it is a rhombus (diamond shaped). I think you are capable of figuring it out.

Answer 22

lol

Answer 23

Good luck with these, I have faith in you. I have to run now, got to buy a bycycle for grandson.

Answer 24

well have fun, thank you so far!!!!

Answer 25

You're welcome, We do have the function remaining area, but there is some cofusing regarding if we have to cut lol. cul