A 110-g bullet is fired from a rifle having a barrel 0.636 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is 13500 + 11000x - 25750x2, where x is in meters.

(a) Determine the work done by the gas on the bullet as the bullet travels the length of the barrel.
____kJ
(b) If the barrel is 1.02 m long, how much work is done?
___kJ

(c) How does this value compare with the work calculated in part (a)?
percent difference = ___%

Question

A 110-g bullet is fired from a rifle having a barrel 0.636 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is 13500 + 11000x - 25750x2, where x is in meters. 

(a) Determine the work done by the gas on the bullet as the bullet travels the length of the barrel.
          ____kJ
(b) If the barrel is 1.02 m long, how much work is done?
            ___kJ

(c) How does this value compare with the work calculated in part (a)?
percent difference =  ___%

anonymous · Answer

$$\int\limits_{0}^{1.02} (13500 + 11000x - 25750x^2)dx$$

anonymous · Answer

= Work

anonymous · Answer

$$ \int\limits_{0}^{.63}(13500 + 11000x - 25750x^2)$$

anonymous · Answer

for both cases

anonymous · Answer

i did that its the percent difference that im kinda confused

anonymous · Answer

divide one amount by the other....  subtract 1 from the result and then multiply by 100 that's the % change

eg  increase from   100 to 120  .... 120/100 = 1.2;     
1.2-1 =.2;    
.2*100 =20%

anonymous · Answer

okk i got it thank you !