Question

How you turn this

1/2PI -1/2[sin(2+PI)-sin2]=1/2PI+sin2?

I used the property of sinx-siny=2[sin((x-y)/2)][cos((x+y))].. But i cant get the answer

Answer 1

Let me clarify, you want to prove the trigonometric identity?

Answer 2

oh wait
nvm
that is incredibly simple

Answer 3

ok so take a look at sin(2-PI),
Your goal is to rewrite that so you can reduce the equation.
Using CAST rule, you will see that adding/subtracting PI will make the sine negative
Therefore: sin(2-PI) = -sin(2)
Plug that back in and reduce the terms, you get the exact equation.
Do you want a diagram?

Answer 4

1/2PI -1/2[sin(2+PI)-sin2]=1/2PI+sin2
1/2PI -1/2[-sin(2)-sin2]=1/2PI+sin2
etcetera

Answer 5

Understand?

Answer 6

sin(2-pi) = -sin(2).. i don understand this part, there is no identify of such "?

Answer 7

and thanks alot for the explanation (:

Answer 8

can u explain, how u get sin(2-pi) = -sin(2)? actually that is the only thing that confused me in this transformation..