How to find another zero when given a zero
Ca you be more specific?
if \(a\) is a zero of a polynomial, then \((x-a)\) is a factor of that polynomial
sure
@TuringTest That's correct but I don't think that's what he means.
i need to know how to find another zero with 2 - 3i is a zero of f(x) = x4 - 4x3 + 14x2 - 4x + 13.
oh wait. yeah.
You can use division to factor the rest of the equation,
thnk u
given what TuringTest said
so use syntetic division?
if a+ib is a root, then a-ib is also the root
complex zeroes come in pairs, so if 2 - 3i is a zero, you simply find its pair..
*root or zero
oh ok
To elaborate on hartnn and ganeshie: If the polynomial has real coefficients then complex roots come in conjugate pairs (a+bi and a-bi). Similarly, if the polynomial has rational coefficients, then irrational roots will come in conjugate pairs as well.
thnk u also CliffSedge wish i could give u medal also! =)
u too hartnn
It's ok, I'm sure I'll get plenty more elsewhere *is smug* In your particular example, if you multiply that complex conjugate pair of factors together, you'll get a quadratic polynomial with real coefficients. You can then factor that out of the original fourth-degree polynomial to yield another quadratic, then it's quadratic formula to find the remaining two roots. Step four: sit back and admire your work.
haha thnks!
thank u everyone!
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