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Mathematics 19 Online
OpenStudy (anonymous):

How to find another zero when given a zero

OpenStudy (anonymous):

Ca you be more specific?

OpenStudy (turingtest):

if \(a\) is a zero of a polynomial, then \((x-a)\) is a factor of that polynomial

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

@TuringTest That's correct but I don't think that's what he means.

OpenStudy (anonymous):

i need to know how to find another zero with 2 - 3i is a zero of f(x) = x4 - 4x3 + 14x2 - 4x + 13.

OpenStudy (anonymous):

oh wait. yeah.

OpenStudy (anonymous):

You can use division to factor the rest of the equation,

OpenStudy (anonymous):

thnk u

OpenStudy (anonymous):

given what TuringTest said

OpenStudy (anonymous):

so use syntetic division?

hartnn (hartnn):

if a+ib is a root, then a-ib is also the root

ganeshie8 (ganeshie8):

complex zeroes come in pairs, so if 2 - 3i is a zero, you simply find its pair..

hartnn (hartnn):

*root or zero

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

To elaborate on hartnn and ganeshie: If the polynomial has real coefficients then complex roots come in conjugate pairs (a+bi and a-bi). Similarly, if the polynomial has rational coefficients, then irrational roots will come in conjugate pairs as well.

OpenStudy (anonymous):

thnk u also CliffSedge wish i could give u medal also! =)

OpenStudy (anonymous):

u too hartnn

OpenStudy (anonymous):

It's ok, I'm sure I'll get plenty more elsewhere *is smug* In your particular example, if you multiply that complex conjugate pair of factors together, you'll get a quadratic polynomial with real coefficients. You can then factor that out of the original fourth-degree polynomial to yield another quadratic, then it's quadratic formula to find the remaining two roots. Step four: sit back and admire your work.

OpenStudy (anonymous):

haha thnks!

OpenStudy (anonymous):

thank u everyone!

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