Factor: 12s^2+25s-7
Do you know the quadratic equation? If you use it to solve for the roots, then the factorization is simply: \[(x-root_1)(x-root_2)\]
hello ,,smagyar" are you from Hungary ? because i am from there too
can you show me how to solve it by splitting the middle term? and my parents are
I have: 12s^2 + 21s +4s -7
okay, so what is a factor of both 21s and 7? What is a factor of both 12s^2 and 4s?
I thought i do the first two then the last two?
No, you want to pair them up by the common factor. Consider how 7 and 21x have a common factor while 4s and 7 don't have a common factor.
7(3s-1)+4s(3s+1) it doesnt match up in the parenthesis?
so i have wrote this question to you there just because ,,magyar" mean ,,hungarian " but suppose you know it sure
Yeah, so you're going to have to split them differently.
You could try \(12x^2 -3s + 28x - 7 \).
Thank you so much i got the answer!
yes haha that is my last name
Join our real-time social learning platform and learn together with your friends!