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Mathematics 8 Online
OpenStudy (anonymous):

Factor: 12s^2+25s-7

OpenStudy (anonymous):

Do you know the quadratic equation? If you use it to solve for the roots, then the factorization is simply: \[(x-root_1)(x-root_2)\]

jhonyy9 (jhonyy9):

hello ,,smagyar" are you from Hungary ? because i am from there too

OpenStudy (anonymous):

can you show me how to solve it by splitting the middle term? and my parents are

OpenStudy (anonymous):

I have: 12s^2 + 21s +4s -7

OpenStudy (anonymous):

okay, so what is a factor of both 21s and 7? What is a factor of both 12s^2 and 4s?

OpenStudy (anonymous):

I thought i do the first two then the last two?

OpenStudy (anonymous):

No, you want to pair them up by the common factor. Consider how 7 and 21x have a common factor while 4s and 7 don't have a common factor.

OpenStudy (anonymous):

7(3s-1)+4s(3s+1) it doesnt match up in the parenthesis?

jhonyy9 (jhonyy9):

so i have wrote this question to you there just because ,,magyar" mean ,,hungarian " but suppose you know it sure

OpenStudy (anonymous):

Yeah, so you're going to have to split them differently.

OpenStudy (anonymous):

You could try \(12x^2 -3s + 28x - 7 \).

OpenStudy (anonymous):

Thank you so much i got the answer!

OpenStudy (anonymous):

yes haha that is my last name

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