Question

how would you write these logarithmic expressions as a single logarithm :
1. 4 log m - log n
2. log 5 - k log 2
3.) log [ base of 6] 5 + log [ base of 6 ] x
4. log { base of 7 ] x + log [base of 7] y - log [base of 7] z

Answer 1

a*ln(b) = ln(b^a)
ln(a)-ln(b) = ln(a/b)
ln(a)+ln(b) = ln(a*b)

use these rules to get the first one and show me what you get

Answer 2

i got log m^4 / n ..... is that right ?

Answer 3

correct

Answer 4

okay so how do i get the answer for the second one ?

Answer 5

@Zekarias

Answer 6

\[\log 5-\log 2^{k}\]\[\log(\frac{ 5 }{ 2^{k} })\]

Answer 7

yea that is exactly wat i got bt now im at the third one and i dont know how to solve it

Answer 8

\[\log_{6}5+\log_{6}x \]\[\log_{6}5x \]

Answer 9

and then would the third one be : log[base 7] xyz

Answer 10

?

Answer 11

AND THE LAST ONE\[\log_{7} x+\log_{7}y-\log_{7}z\]\[\log_{7}(\frac{ xy }{ z })\]

Answer 12

thank you so much for ur help