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Mathematics 16 Online
OpenStudy (anonymous):

How must I simplify this?

OpenStudy (anonymous):

Simplify what?

OpenStudy (anonymous):

Give me a sec

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[\frac{ \sqrt[3]{a} }{\sqrt{5a} } . \frac{ a \sqrt{30} }{ \sqrt[3]{60a^2} }\]

OpenStudy (anonymous):

There we go!

OpenStudy (anonymous):

Okay, so first thing is first\[\Large\frac{a}{b}\cdot \frac{c}{d}=\frac{a\cdot c}{b\cdot d}\] Also: \[\Large\sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b}\] Can you start with using these properties?

OpenStudy (anonymous):

Yes, I see...

OpenStudy (anonymous):

But what I did, was changing the square roots to powers of fractions

OpenStudy (anonymous):

Alright, do you know the properties of exponents?

OpenStudy (anonymous):

Where are you stuck?

OpenStudy (anonymous):

Well, somewhere I had \[\frac{ 30a^\frac{ 11 }{ 6 } }{ 5a^\frac{ 1 }{ 2 } . (60a^\frac{ 7 }{ 3 }) }\]

OpenStudy (anonymous):

I guess I probably multiplied the bottom part of that fraction totally wrong.

OpenStudy (anonymous):

Remember that \[\Large x^{-n} = \frac{1}{x^n}\]

OpenStudy (anonymous):

Yes, I know.

OpenStudy (anonymous):

You need to keep your parenthesis when you converting roots into fractional exponents.

OpenStudy (anonymous):

Oh, okay

OpenStudy (anonymous):

Did I convert them correctly?

OpenStudy (anonymous):

No, you messed up on parts

OpenStudy (anonymous):

Oh... hmmm, which part

OpenStudy (anonymous):

Well, the whole thing is kinda messy because you don't have parenthesis and such. But

OpenStudy (anonymous):

\[\frac{ (a)^\frac{ 1 }{ 3} }{ (5a)^\frac{ 1 }{ 2 } } . \frac{ a(30)^\frac{ 1 }{ 2 } }{ (60a^2)^\frac{ 1 }{ 3 } }\]

OpenStudy (anonymous):

How about that.

OpenStudy (anonymous):

Good!

OpenStudy (anonymous):

Okay :))

OpenStudy (anonymous):

What I did after that, was something like this:

OpenStudy (anonymous):

\[\frac{ (a)^\frac{ 4 }{ 3 } . (30)^\frac{ 1 }{ 2 } }{ (5a)^\frac{ 1 }{ 2 } . (60a^2)^\frac{ 1 }{ 3 } }\]

OpenStudy (anonymous):

You can type \Large in front to make it more readable.

OpenStudy (anonymous):

\[\frac{1}{8} + 1 = \frac{1}{8}+\frac{8}{8} = \frac{9}{8}\]

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