How must I simplify this?
Simplify what?
Give me a sec
ok
\[\frac{ \sqrt[3]{a} }{\sqrt{5a} } . \frac{ a \sqrt{30} }{ \sqrt[3]{60a^2} }\]
There we go!
Okay, so first thing is first\[\Large\frac{a}{b}\cdot \frac{c}{d}=\frac{a\cdot c}{b\cdot d}\] Also: \[\Large\sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b}\] Can you start with using these properties?
Yes, I see...
But what I did, was changing the square roots to powers of fractions
Alright, do you know the properties of exponents?
Where are you stuck?
Well, somewhere I had \[\frac{ 30a^\frac{ 11 }{ 6 } }{ 5a^\frac{ 1 }{ 2 } . (60a^\frac{ 7 }{ 3 }) }\]
I guess I probably multiplied the bottom part of that fraction totally wrong.
Remember that \[\Large x^{-n} = \frac{1}{x^n}\]
Yes, I know.
You need to keep your parenthesis when you converting roots into fractional exponents.
Oh, okay
Did I convert them correctly?
No, you messed up on parts
Oh... hmmm, which part
Well, the whole thing is kinda messy because you don't have parenthesis and such. But
\[\frac{ (a)^\frac{ 1 }{ 3} }{ (5a)^\frac{ 1 }{ 2 } } . \frac{ a(30)^\frac{ 1 }{ 2 } }{ (60a^2)^\frac{ 1 }{ 3 } }\]
How about that.
Good!
Okay :))
What I did after that, was something like this:
\[\frac{ (a)^\frac{ 4 }{ 3 } . (30)^\frac{ 1 }{ 2 } }{ (5a)^\frac{ 1 }{ 2 } . (60a^2)^\frac{ 1 }{ 3 } }\]
You can type \Large in front to make it more readable.
\[\frac{1}{8} + 1 = \frac{1}{8}+\frac{8}{8} = \frac{9}{8}\]
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