Question

x^5 + x^3 + 8x^2 + 8

factor

Answer 1

so far i got

[x^3(x^2+1)+ 8(x^2+1)]


(x^2+1)(x^3+8)

Answer 2

Well theres a formula for (x^3+8)
a3 + b3 = (a + b)(a2 – ab + b2)
a3 – b3 = (a – b)(a2 + ab + b2)

Would yours be the top one or the bottom one?

Answer 3

the bottom

Answer 4

It would be the top one because you are adding, right?

Answer 5

your right

Answer 6

so what is the cube root of 8?

Answer 7

2

Answer 8

(x-2)(x2+2x+4)

Answer 9

remember you're using the first formula\

so it should be
(a+b)(a^2-ab+b^2)

Answer 10

you have all the numbers right but the signs need to be changed

Answer 11

(x+2)(x2-2x+4)(x2+1)

Answer 12

right!
no what about (x^2 +1)
can you factor that?

Answer 13

x= +_ i .. no?

Answer 14

right

Answer 15

so (x+i)(x-i)

Answer 16

so what's the whole thing factored out?

Answer 17

(x+2)(x2-2x+4)(x+i)(x-i)

Answer 18

I have one more question from you, can you factor (x^2-2x+4)?

Answer 19

no would you use the quadratic formula

Answer 20

very good!

Answer 21

(x+2)(x+(-1+i sqrt{3})(x+(-1-i sqrt{3})(x+i)(x-i)

Answer 22

yeah, thats about right.

Answer 23

thx for your help jackellyn!!!

Answer 24

no problem :)