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Mathematics 12 Online
OpenStudy (anonymous):

tough probability problem

OpenStudy (anonymous):

OpenStudy (anonymous):

on c)

OpenStudy (anonymous):

why is it (1+p)^(m-r) instead of (p)^(m-r)

OpenStudy (anonymous):

@zarkon, when you come on can you take a look?

OpenStudy (bahrom7893):

@satellite73

OpenStudy (anonymous):

whew i can explain that one (and not embarrass myself) because it is algebra

OpenStudy (anonymous):

the probability that you decide to buy a ticket and it loses is \(\frac{1-p}{2}\) viewing this as bernoulli trials (independent repeated experiments with only two outcome) the the formula is \[P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}\] but in this case \[p=\frac{1-p}{2}\] and therefore \[1-p=1-\frac{1-p}{2}=\frac{1+p}{2}\]

OpenStudy (anonymous):

i guess what i wrote is silly, i should have made the first \(p\) a \(p^*\) or some other variable

OpenStudy (anonymous):

I see, all those 'p' were confusing me

OpenStudy (anonymous):

thanks for your help

OpenStudy (anonymous):

yw

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