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Mathematics 104 Online
OpenStudy (anonymous):

If 5 of a company's 12 delivery trucks do not meet emission standards and 4 of the twelve trucks are randomly pick for inspection, what is the probability that none of them meet emission standards

OpenStudy (anonymous):

two ways to proceed. simplest way is to say first one doesn't, then second one doesn't , then third on doesn't then fourth one doesn't and compute \[\frac{5}{12}\times \frac{4}{11}\times \frac{3}{10}\times \frac{2}{9}\]

OpenStudy (anonymous):

second way is to say the number of ways to pick 4 out of 12 is \(\binom{12}{4}\) and the number of ways to pick 4 out of the 5 that don't meet the standards is \(\binom{5}{4}=5\)

OpenStudy (anonymous):

and then compute \[\frac{\dbinom{5}{4}}{\dbinom{12}{4}}=\frac{5}{792}\]

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