use the elimination method to figure the systems of equations: 5u+2v=-17 *1 3u+v=-5 *2 5u+2v=-17 6u+2v=10 use elimination 11u=-7 divide both sides by 11 u=-7/11?? then plug in to first formula and got if u =-7/11 5(-7/11)-2v=-17 35/11+2y=-17 which we have to divide both by 35/11 which gives me 2v=-17 divide by 35/11 and i get hella lost
You should have gotten this 5u + 2v = -17 -6u - 2v = 10 -u = -7 7 = u
ok so if I change to a 7. Still stuck u=-7/11?? then plug in to first formula and got if u =7/11 5(7/11)-2v=-17 35/11+2y=-17 which we have to divide both by 35/11 which gives me 2v=-17 divide by 35/11 and i get hella lost
srbbw44, You made one small error when multiplying the second equation times 2. you should have gotten: 5u+2v=-17 6u+2v=-10 use elimination Not 6u+2v=10 Solve with those two.
so would that make my -7
so u would get 11u=-27
divide both sides by 11 to get a crazy problem 2v=-17 divide that by 135/11
If you add the equations like that you would get 11u+4v=-27 You need to eliminate one variable.
Yeah, don't pay attention to anything I did
Subtract one equation from the other to eliminate the v variable and then solve for u.
hero i messed up the equation not u
I get either -u = -7 or u = 7 depending on which equation you subtract from the other. I think you did this correctly, Hero.
or am I missing the sarcasm ;o)
no ideal i can plug the u=-7 v= 9 but it fits in the first equation but not the second one when we check our math from our origanal problem
I don't get u = -7 Begin with: 5u + 2v = -17 6u + 2v = -10 Subtract the 2nd from the 1srt equation: 5u + 2v = -17 -(6u + 2v = -10) Use distributive property: 5u + 2v = -17 -1(6u + 2v) = -1(-10) Written out: 5u + 2v = -17 -6u + -2v = 10 Yields: -u = -7 Meaning: u = 7 Substitute that into both equations. I het the same value in each with u = 7 solving for v. You?
The long way I wrote it is my usual way of doing these because when I make an error, it is almost always that I missed a sign.
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