Factor completely x^(2)(x+4)(-6x(x+4)+9(x+4). Ive gotten to (x+4)(X^(2) - 6X +9). I dont know where to go from here.

Question

Factor completely   x^(2)(x+4)(-6x(x+4)+9(x+4). Ive gotten to (x+4)(X^(2) - 6X +9).  I dont know where to go from here.

anonymous · Answer

recognize the second factor as a perfect square

anonymous · Answer

$$factor:   x^{2}-6x+9$$

anonymous · Answer

the factors are 0,-4,2/3

anonymous · Answer

i think for the factors of $$f(x)=a \times b \times c$$
a=0,b=0,c=0 separately
where a,b,c are the functions of x

aimmebgood · Answer

that doesnt really help.

anonymous · Answer

maybe this will help 
$$(a-b)^2=a^2-2ab+b^2$$

anonymous · Answer

replace $a$ by $x$ and $b$ by  $3$

anonymous · Answer

making 
$$x^2-6x+9=(x-3)^2$$

anonymous · Answer

i mean to say assume $$a=x ^{2},b=x+4,c=(-6x(x+4)+9(x+4)$$
and then find the zeroes

anonymous · Answer

and a "final answer" of 
$$(x+4)(x-3)^2$$ to the problem

anonymous · Answer

it says nothing about finding zeros
it says to factor

anonymous · Answer

@aimmeBgood your first step was good 
next step is to rewrite $x^2-6x+9$ as $(x-3)^2$ hope it is clear

anonymous · Answer

the factors thus could be found as 
x+4
x-2/3
sorry but i interpret the question as
$$x ^{2}(x+4)(-6x(x+4)+9(x+4))$$

anonymous · Answer

sorry its x+3/2
instead of x-2/3

anonymous · Answer

also i forgot to mention that x is also its factor