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An 82 Kg pilot is flying a stunt airplane pulls out of a dive at a constant speed of 540 km/h. What force is applied on the pilot by the plane seat at the lowest point in the pullout?
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Minimum radius is 3.3*10^2m. The answer is 6.4*10^3 N.
My initial answer was 5590.909090...N.
So what is the formula for centripetal force?
Fc=mv^2/r
And since he is at the bottom of the circle, the centripetal force is in the same direction as the force of gravity. So they are both just added, right?
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So \(\Large F_{net} = m\frac{v^2}{r}+ma_{gravity}\) We have \(m, v, r, a_{gravity}\) right? So does this get you the correct answer?
lemme try this one out first. thx for the help and immediate response
is gravity suppose to be negative?
@wio
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