How do you solve this? If a die is rolled five times, find the probability of getting at least one 6.

Question

anonymous · Answer

are you saying 1/6th or just 1 6

anonymous · Answer

the probability of rolling a six would be 5/6

anonymous · Answer

since you are rolling it 5 times and there are 6 sides to a die

hartnn · Answer

the probability of getting atleast 1 6 = 1- probability of getting none of the 6 in any of the 5 rolls
probability of not getting a 6 is 5/6
the probability of getting atleast 1 6 = 1-(5/6)^5
understood?

anonymous · Answer

one "6"

hartnn · Answer

u got how (5/6)^5 ?

anonymous · Answer

got it! thanks

hartnn · Answer

welcome ^_^

kropot72 · Answer

Using the binomial distribution the probability of throwing one 6 in five rolls is:$$P(one6)=\left(\begin{matrix}5 \ 1\end{matrix}\right)\times \frac{1}{6}\times (\frac{5}{6})^{4}=(\frac{5}{6})^{5}$$