Question

If tan A - tan B = x and cot B - cot A =Y , pt COT (a-b) = 1/X + 1/Y

Answer 1

@akash123

Answer 2

sin(A-B)/ cosA*cosB =1/x from Tan A - tan B=x

Answer 3

okay !

Answer 4

then ?

Answer 5

and sin(A-B)/ sinA* SinB=y from cotB- cotA =y
sin(A-B)/ cosA*cosB =x from Tan A - tan B=x

tanA*tanB= x/y

Answer 6

@akash123
sin(A-B)/ cosA*cosB =x from Tan A - tan B=x

Answer 7

cot(A-B) = [ cot A* cot B+1] / ( cot B - cot A)

Answer 8

yes...thanks...I have corrected it later

Answer 9

sin(A-B)/ sinA* SinB=y from cotB- cotA =y
sin(A-B)/ cosA*cosB =x from Tan A - tan B=x
divide 2nd by 1st

then u'll get
tanA*tanB= x/y

Answer 10

yes i understood that !

Answer 11

now use the identity
cot(A-B) = [ cot A* cot B+1] / ( cot B - cot A)

and substitute the value of cot A* cot B and (cot B- cot A)
then u'll get the answer

Answer 12

another way @sauravshakya
write the reciprocal f 1st and 2nd equation and add both
then simplify it.

Answer 13

Yep... I would go with that....

Answer 14

okay got it :)
thank you !

Answer 15

:)