._.
oh wait, couldn't i just say ABCD is a rhombus. Given. Diagonals bisect interior angles. Property of a rhombus?
would that work, or is that too easy to be true
By sss similarity theorem \[\Delta ABC = {\Delta}ADC\]thus <ACB = <ACD
but this is straight out of the lesson
but how would that prove that the diagonals bisect the angles?
ooh i think i see what you mean
since this two angles <ACB and <ACD are congruent then we can conclude that half <BCD is equal to one of them.
Given, sides AB, AD, BC, and CD are congruent. Line AC = Line AC by the Reflexive Property. Triangles ABC and ADC are congruent by SSS. Angles ACB and ACD are congruent by CPCTC. Diagonal AC bisects Angle BCD by definition of an angle bisector. would that be the whole thing or would i also have to prove that Diagonal BD bisects as well?
guys? :/
@hartnn do you know this?
diagnols means both, u need to do same thing in triangle ABD and BCD
sigh. ok, thanks :)
do i have to state the given information again?
nopes, once is enough
ok, just to make sure before i send it in. does this look right? Given, sides AB, AD, BC, and CD are congruent. Line AC = Line AC by the Reflexive Property. Triangles ABC and ADC are congruent by SSS. Angles ACB and ACD are congruent by CPCTC. Diagonal AC bisects Angle BCD by definition of an angle bisector. Line BD = Line BD by the Reflexive Property. Triangles ABD and CBD are congruent by SSS. Angles ADE and CDE are congruent by CPCTC. Diagonal BD bisects Angle ADC by definition of an angle bisector. Therefore, the diagonals of the rhombus bisect the interior angles.
seems right.....don't u have an habit of numbering the equations? in that way u could have used AB=AD=BC=CD ---->(1) this at both places......
what do you mean?
how would you write it?
Given, sides AB, AD, BC, and CD are congruent.---->(1) Line AC = Line AC by the Reflexive Property.------>(2) From (1) and (2), Triangles ABC and ADC are congruent by SSS. Angles ACB and ACD are congruent by CPCTC. Diagonal AC bisects Angle BCD by definition of an angle bisector. Line BD = Line BD by the Reflexive Property.------>(3) From (1) and (3), Triangles ABD and CBD are congruent by SSS. Angles ADE and CDE are congruent by CPCTC. Diagonal BD bisects Angle ADC by definition of an angle bisector. Therefore, the diagonals of the rhombus bisect the interior angles. basically same thing, but does it *look* better ?
i guess, they just didn't teach it like that :/ i'm not sure if they would like that or not
then what you have written is complete.....u can use that
alright, thanks :)
welcome.
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