Question

Solve d^2y/dx^2 = a/(b-y)^2

Answer 1

separate the variables

Answer 2

\[\frac{\text d^2y}{\text dx^2} =\frac a{(b-y)^2}\]
\[{(b-y)^2}\cdot{\text d^2y} = a\cdot\text dx^2\]
\[\iint{(b-y)^2}\cdot{\text d^2y} = \iint a\cdot\text dx^2\]

Answer 3

it is \[d^2y \] not \[dy^2\] right??

Answer 4

right ,

Answer 5

then how can we double integrate?