numerical analysis Bairstow method why the first initial guess doesn't lead us to answer always ???
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see u man
@Mikael see this plz
which we use for finding all roots of a polynomial...help would be appreciated
how our initial guess increases the rate of convergence
Ok I will have to read more and think. Basically there should be a procedure that deals with quadratic root troubles. Initial guess is small change , forget it. I have some idea but have to test it. Imagine that qudr. root is NOT quadratic root. How ? Several ways are possible - you invent, and I invent....
Then we talk.
in 1-2 days.
thank u...i'll check this :)
@mahmit2012
Wait, @mukushla I think I might know.
Bairstow's method relies on newton's method to calculate the quadratic's coeffs, right?
yeah we extract quadratics from a polynomial and then solve for all of its roots...
But newton's method essentially makes the assumption that \[\Delta y = \Delta x dy\]
So if I have some function where the tangent line (dy/dx) has a slope negative to the actual secant line (delta y/delta x) that it's approximating, then you'll get farther from where you started.
Ex:|dw:1349025207545:dw|
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