Question

If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and third equations, then the second and third equations.

x – y + 2z = –2
2x + 2y + z = 7
3x + 3y – z = 3

2x + 2y = 7
3x + 3y = 3

2x + 2y = 7
5x + 5y = 10

7x + 5y = 4
3x + 3y = 3

7x + 5y = 4
5x + 5y = 10

Answer 1

@ghazi , @experimentX ?

Answer 2

what's your point in it ? do you wants us to check your answer?

Answer 3

first multiply the 3rd equation by 2 & add it to the 1st equation to eliminate z. What do you get?

Answer 4

@yummydum i think you've already done everything

Answer 5

wait there is a mistake

Answer 6

@ghazi this is a question with its options not a worked out problem

Answer 7

okay ....

Answer 8

add equation 2 and 3

Answer 9

what you got?

Answer 10

@rajathsbhat 7x+5y=4 and then id get 5x+5y=10

Answer 11

so its D :) ..THNAKYOU :)

Answer 12

just add these 2x+2x+z=7 and 3x+3y-z=3

Answer 13

there you go :)

Answer 14

that's correct