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solve: a^2 · a^3 · a^-4
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do you know the answer?
use these formula ..a^-n = 1/a^n , a^n . a^m = a^(n+m) and a^n/a^m = a^(n-m) and you can get the answer quick
it's not a^9 though..
ofcourse it's not, one of the power is negative...check that again :)
see that's what confuses me, but I thought when you flip the exponent to make it positive, you add it as a positive exponent?
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would it be a^1?
correct
okay, So you're not supposed to flip it then? :S
it's two positive powers 2 and 3..you add..one negative power 4 ..you subtract
ty
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yw :)
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