Find the derivative of the following function.
\[y=6(1-(t/12))^2\]
Okay, so have you tried expanding the expression?
\[y=6(1-(t/12))^2 = 6(1-(t/12))(1-(t/12)) =?\]
I've tried using the chain rule and then the product rule to get the answer. But its not the right answer.
hmmmm why are you exapnding?
Oh our teacher wants us to answer the question using either the chain, product, or the quotient rule. Sorry.
You need to use the chain rule
Okay, I wasn't sure what the curriculum was but anyway. Do you remember the chain rule?
So use the chain rule by bringing down the exponent and subtracting one form the exponent basically use the exponent rule first
\(\large y'=6*2(1-{t \over 12})^{2-1}\)
next step we derive the -t/12 in the bracket \(\large y'=6*2(1-{t \over 12})^{2-1}*-1\) \(\large y'=-12(1-{t \over 12})\)
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