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Mathematics 6 Online
OpenStudy (anonymous):

Find the derivative of the following function.

OpenStudy (anonymous):

\[y=6(1-(t/12))^2\]

OpenStudy (anonymous):

Okay, so have you tried expanding the expression?

OpenStudy (anonymous):

\[y=6(1-(t/12))^2 = 6(1-(t/12))(1-(t/12)) =?\]

OpenStudy (anonymous):

I've tried using the chain rule and then the product rule to get the answer. But its not the right answer.

OpenStudy (swissgirl):

hmmmm why are you exapnding?

OpenStudy (anonymous):

Oh our teacher wants us to answer the question using either the chain, product, or the quotient rule. Sorry.

OpenStudy (swissgirl):

You need to use the chain rule

OpenStudy (anonymous):

Okay, I wasn't sure what the curriculum was but anyway. Do you remember the chain rule?

OpenStudy (swissgirl):

So use the chain rule by bringing down the exponent and subtracting one form the exponent basically use the exponent rule first

OpenStudy (swissgirl):

\(\large y'=6*2(1-{t \over 12})^{2-1}\)

OpenStudy (swissgirl):

next step we derive the -t/12 in the bracket \(\large y'=6*2(1-{t \over 12})^{2-1}*-1\) \(\large y'=-12(1-{t \over 12})\)

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