Question

\[F = 9\div5C + 32\]

Answer 1

good to know :)

Answer 2

Can you solve for C using the formula?

Answer 3

ite Centigrade to faranheit conversion

Answer 4

sure, i can,
can u ?

Answer 5

No thats why I asked, I need help

Answer 6

subtract 32 from both sides, what u get ?

Answer 7

\[F- 32 = 9\div5C\]

Answer 8

right, now can u flip the fraction?
like if a/b=c/d
then
b/a=d/c

Answer 9

\[1\div F-32 = 5\div 9C \] is that correct?

Answer 10

just don't forget to keep brackets
1/(F-32)=5C/9

Answer 11

Okay, do I cross multiple now?

Answer 12

now you can multiply both sides by 9/5
so that you isolate C on right side

Answer 13

when I multiply 9/5 by both sides, do I cross multiple or multiply numerator by numerator and denominator by denominator?

Answer 14

multiply*

Answer 15

(9/5)(1/F-32) = 5C/9 * 9/5

Answer 16

so whats the final answer?

Answer 17

on right side, u get only C
on left u get \(\large \frac{9}{5(F-32)}\)

Answer 18

thats your final answer

Answer 19

Thanks so much for your assistance !

Answer 20

welcome :)

Answer 21

can i clarify something?