Question

x^2-?+9

Answer 1

like i have no idea what to do??

Answer 2

Trying to make a perfect square?

Answer 3

yes!

Answer 4

take square-root of constant and double it.

Answer 5

Perfect square has the form:
\[(x+a)^2 \rightarrow (x+a)(x+a) \rightarrow x^2 +2ax +a^2\]

Answer 6

So the middle coefficient (2a) is two times the square-root of the constant (a^2).

Answer 7

dont know if i did it right but i did it twice i got 6x and 30x idk

Answer 8

Where did the 30x come from?

Answer 9

i have no clue im so lost

Answer 10

Step one: look at the constant at the end, 9.
The square-root of 9 is 3.
Step two: double the 3 to 6, so the middle term must be -6x.

Answer 11

You can verify the following:
\[x^2-6x+9 = (x-3)^2\]

Answer 12

ok thanks so much now that you explained it i get it so you just have to double it i dont think i did that thanks again

Answer 13

y.w.

Answer 14

wouldnt i get the same answer if i had 9x^2+?+25

Answer 15

wait it might be 30x this time

Answer 16

Think of it in terms of (ax+b)^2

Answer 17

ok

Answer 18

(and yes, 30x works)

Answer 19

ok i just wanted to check thanks agian lol