linear equations how to do -3x+y=2?
y-intercept and x-intercept
how do i solve for them?
First, solve for y. The y intercept will be where x=o. Therefore, plug 0 into your new equation and this should yield the y intercept. Likewise, if you plug zero in for y, you should get the x intercept.
y = mx+b -3x + y = 2 (rewrite it to y-intercept) y= 3x+2 solve for y-intercept by changing the value of x to zero y= 3(0) + 2 y = 2 solve for x-intercept by changing the value of y to zero do the rest :)
so for x is -3(0)+y=2?
or for y do i leave it as 2 in it then solve for x?
it will be: y = mx+b y= 3x + 2 (solve for x-intercept by changing the value of y to zero) 0 = 3x + 2 -3x = 2 (solve for x by dividing the coefficient with -3) x = -2/3
values: x = -2/3 y = 2
if I was to do this for a different problem would I do the same thing?
yes! Just make sure to solve for y first so you have y=mx+b
yes :) when you are given relatively same equation, just always solve the y-intercept and x-intercept. note that y-intercept means the part in the cartesian plane where the line touches the y-axis which, the value of x is zero. And for the x-intercept, it would be the part of the cartesian plane where the line touches the x-axis, which the value of y is zero.
can you give me a example and I try to do it and see if I get it?
thank you.
how would i graph -2/3 on a graph? it doesnt have that low
it doesn't support it
oh i see never mind thank you.
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