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Solve for x 10^(log12x+6)=5
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do you know what this equals:\[b^{\log_bx}=?\]
no i dont
ok, look at it this way, you this rule I presume - if:\[\log_bx=y\implies x=b^y\]
*you know this...
yes
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good, so now substitute into the last expression the value for y and we get:\[x=b^y=b^{\log_bx}\]
since \(y=\log_bx\)
make use of this rule to simplify your equation
I assume your equation is:\[10^{\log_{10}(12x+6)}=5\]
yea so is it 10^5=12x+6?
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no - why did you put \(10^5\)?
the 5 should just remain as it was
\[10^{\log_{10}(y)}=y\]
that is the identity you need to use here.
ahh ok i get it. thank you so much
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yw :)
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